TM 5-3895-370-14&PExample 1Bearing clearance = 0.003 in. (0.08 mm)1/2 of bearing clearance = 0.0016 in (0.04 mm)6 o'clock position reading = 0.008 in (0.20 mm)0.008 in (0.020 mm)-0.0016in(0.04mm)0.0064 in (0.16 mm)In the above example, 0.0064 in (0.16 mm) is the adjusted bearing clearance.(6)After determining the adjusted bearing clearance, the Total Indicator Reading (TIR) must be determined.Proceed as follows:(a)Add 12 o'clock position measurement, obtained from step (3), and bearing clearance adjustment, asdetermined from step (5). See Example 2.Example 20.000 in (0.00 mm) (12 o'clock measurement)+0.0064in(0.16mm)(adjusted bearing clearance)0.0064 in (0.16 mm) (total vertical reading)(b)Add 3 o'clock and 9 o'clock position measurements, obtained from step (3). See Example 3.Example 30.003 in (0.08 mm) (3 o'clock measurement)+0.001in(0.03mm)(9 o'clock measurement)0.005 in (0.11 mm) (total horizontal reading)(c)Add totals from the above steps (a) and (b) to get Total Indicator Reading. See Example 4.Example 40. 0064 in (0.16 mm) (total vertical reading from step [a])+0.001in(0.03mm)(total horizontal reading from step [b])0.0074 in (0.19 mm) (Total Indicator Reading)(7)After determining the allowable TIR for thisengine, measure flywheel housing bore atposition A Normal bore diameter is between17.625 to 17.630 in. (447.675447.802 mm). IfTIR, as determined in the above steps, is otherthan 0.008 in (0.20 mm), replace flywheelhousing. If TIR is 0.008 in (0.20 mm), thenflywheel housing-to-concentricity is acceptable.5-47
Integrated Publishing, Inc. - A (SDVOSB) Service Disabled Veteran Owned Small Business
